How do you solve $\frac { x + 5} { 2} + 3= x - 2$ ?

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Answer 1 · 2017-02-02T15:46:31

$x=15$

$(x+5)/2+3=x-2$

multiply both sides by 2

$:.x+5+6=2(x-2)$

$:.x+11=2x-4$

$:.x-2x=-11-4$

$:.-x=-15$

multiply both sides by $-1$

$:.x=15$

substitute $x=15$

$:.(15+5)/2+3=15-2$

$:.20/2+3=13$

$:.10+3=13$

$:.13=13$

How do you solve \frac { x + 5} { 2} + 3= x - 2\frac { x + 5} { 2} + 3= x - 2?