How do you graph $y=2(1/3)^(x+1)-3$ ?

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Answer 1 · 2017-02-06T08:50:02

Plug and plot

I would just try values.

if $x = -2$ then $y= 3$

if $x =-1$ then $y= -1$

if $x = 0$ then $y= -7/3$

if $x = 1$ then $y= -25/9$

Then graph, connecting the points
graph{2(1/3)^(x+1)-3 [-10, 10, -5, 5]}

How do you graph y=2(1/3)^(x+1)-3y=2(1/3)^(x+1)-3?