How do you solve #4 - (-7-k) > 2 (k+3)#?

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Answer 1 · 2017-02-07T05:49:06

#k < 5#

Solve like you would a standard multi-step equation.

Since it seems you are new to multi-step equations, it helps to first write the equation as

#4+(-1)(-7-k)>2(k+3)#
Distribute the coefficient to the binomial (a fancy term for "multiply -1 by -7-k and 2 by k+3) to remove the brackets.

You get #4+7+k>2k+6" "# Pretty straightforward from here.

#11+k>2k+6#

#k>2k-5#

#-k> -5#

THE LAST STEP IS CRUCIAL. If you ever multiply or divide by a negative, real number than you must switch the inequality sign.

The final answer is #k<5#