How do you write the equation #y+3/5=-4(x-1/2)# in slope intercept form? Algebra Forms of Linear Equations Write a Function in Slope-Intercept Form 1 Answer Munu Feb 7, 2017 #y+3/5=-4(x-1/2)# #y=-4x+2-3/5# #y=-4x+(10-3)/5# #y=-4x+7/5# Answer link Related questions How do you determine the #(x,y)# point given #f(x)=y#? How do you evaluate functions? How do you write an equation for a line with m=3.5 and #f(-2)=1#? What are the two points if you are given #f(-1)=2# and #f(0)=-6#? How do you write an equation for a line given #f(-1)=1# and #f(1)=-1#? How do you write an equation for a line given #m=-7# and #f(2)=-1#? How do you determine the slope given #f(-4)=2# and #f(0)=3#? How do you write an equation of the line with slope -3 and y-intercept (0,-5)? How do you find the slope-intercept form of the equation of the line that passes through (-2,... How do you write the slope intercept form of the equation of the line through the given point... See all questions in Write a Function in Slope-Intercept Form Impact of this question 1620 views around the world You can reuse this answer Creative Commons License