How do you evaluate $2 \times {(3 x + 4)}^{2}$ $2\times ( 3x + 4) ^ { 2}$ ?

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How do you evaluate $2 \times {(3 x + 4)}^{2}$ $2\times ( 3x + 4) ^ { 2}$ ?

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Answer 1 · 2017-02-07T20:50:12

18 $x^{2}$ $x^2$ + 48 $x$ $x$ + 32

Explanation:

Use the double distributive property (also known as the FOIL method) to first solve $(3$ $(3$ x $+ 4)^{2}$ $+ 4)^2$ . So, multiply 3x by 3x, multiply 3x by 4, multiply 4 by 3x, multiply 4 by 4, then add it all together, resulting in 9 $x^{2}$ $x^2$ + 24 $x$ $x$ + 16. Lastly, multiply each number by 2, which will give you 18 $x^{2}$ $x^2$ + 48 $x$ $x$ + 32.

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How do you evaluate $2 \times {(3 x + 4)}^{2}$ $2\times ( 3x + 4) ^ { 2}$ ?

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