Two charges of $- 1 C$ $-1 C$ and $2 C$ $2 C$ are positioned on a line at points $- 2$ $-2$ and $2$ $2$ , respectively. What is the net force on a charge of $2 C$ $2 C$ at $1$ $1$ ?

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Two charges of $- 1 C$ $-1 C$ and $2 C$ $2 C$ are positioned on a line at points $- 2$ $-2$ and $2$ $2$ , respectively. What is the net force on a charge of $2 C$ $2 C$ at $1$ $1$ ?

1 Answer

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Answer 1 · 2017-02-09T07:32:32

The answer is
$F_{21} = 2.25 * 10^{9}$ $F_21=2.25**10^9$

Explanation:

We all know that they will exert force equal to
$F = k q_{1} * q_{2} / r^{2}$ $F = kq_1**q_2//r^2$
So we can put $q_{1} = 2 and q_{2} = 1$ $q_1 = 2 and q_2= 1$
As sign is never considered and r = 4 from -2 to +2..and $k = 9 * 10^{9}$ $k=9**10^9$

You will get $2.25 * 10^{9}$ $2.25**10^9$ as answer

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Two charges of $- 1 C$ $-1 C$ and $2 C$ $2 C$ are positioned on a line at points $- 2$ $-2$ and $2$ $2$ , respectively. What is the net force on a charge of $2 C$ $2 C$ at $1$ $1$ ?

1 Answer

Explanation:

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Two charges of −1C -1 C and 2C 2 C are positioned on a line at points −2 -2 and 2 2 , respectively. What is the net force on a charge of 2C 2 C at 1 1 ?

1 Answer

Explanation:

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Two charges of $- 1 C$ $-1 C$ and $2 C$ $2 C$ are positioned on a line at points $- 2$ $-2$ and $2$ $2$ , respectively. What is the net force on a charge of $2 C$ $2 C$ at $1$ $1$ ?