A ball with a mass of $12 kg$ moving at $7 m/s$ hits a still ball with a mass of $17 kg$ . If the first ball stops moving, how fast is the second ball moving? How much kinetic energy was lost as heat in the collision?

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Answer 1 · 2017-02-09T08:14:52

The answer is $V_2 =4.94 ~5$
And loss in KE = 87.89 joule or 88 joules approx

According to the conservation of momentum
$m_1v_1+m_2v_2= m_1V_1+m_2V_2$

$12** 7 = 17** V_2$
$V_2=4.94m//s$

Now $Delta KE=1//2(m_1m_2//m_1+m_2)(1-e^2)(v_1-v_2)^2$

And e= relative velocity of separation $//$ relative velocity of approach.

Solving it we get the value of loss in KE :)

A ball with a mass of 12 kg12 kg moving at 7 m/s7 m/s hits a still ball with a mass of 17 kg17 kg. If the first ball stops moving, how fast is the second ball moving? How much kinetic energy was lost as heat in the collision?