Question

How do you find the exact value of `arctan [tan (-(2pi)/3)]`?

Answer 1

`-(2pi)/3`

Explanation:

It is defined that `f^-1(f(x))=x`, or when you plug a value into a function, and then plug the outputted value into the inverse function, you will get the value you started with.

Read the intro for more info about inverse functions

Since `arctan(x)` is identical to `tan^-1(x)`, we can use the above property of mathematics to say that `tan^-1(tan(-(2pi)/3)) = -(2pi)/3`