How do you differentiate #([s^4] - 8)^ .25#?

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Answer 1 · 2017-02-12T09:32:04

#(s^4-8)^(-3/4)*s^3#

Use the power rule to find the derivative of the outside

#(s^4-8)^(1/4)#

#(1/4)(s^4-8)^((1/4-1)#

But then you have to times this by the derivative of the inside which in this case is the derivative of #(s^4-8)#

#(1/4)(s^4-8)^(1/4-1)# times #4s^3#

#1/4(s^4-8)^(-3/4)*4s^3#

#(s^4-8)^(-3/4)*s^3#