How do you simplify ${(p^{\frac{3}{2}})}^{- 2}$ $(p^(3/2))^-2$ ?

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Answer 1 · 2017-02-13T09:33:44

$\frac{1}{p^{3}}$ $1/p^3$

Remember:

${(a^{m})}^{n} = a^{m \times n}$ $(a^m)^n = a^(m xxn)$

In this example:

${(p^{\frac{3}{2}})}^{- 2} = p^{- \frac{6}{2}} = p^{- 3}$ $(p^(3/2))^-2 = p^(-6/2) = p^-3$

$= \frac{1}{p^{3}}$ $= 1/p^3$

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