How do you determine #sectheta# given #costheta=2/3,0^circ<theta<90^circ#? Trigonometry Right Triangles Relating Trigonometric Functions 1 Answer moutar Feb 15, 2017 #3/2# Explanation: #sectheta = 1/(costheta) = 1/(2/3) = 3/2# Answer link Related questions What does it mean to find the sign of a trigonometric function and how do you find it? What are the reciprocal identities of trigonometric functions? What are the quotient identities for a trigonometric functions? What are the cofunction identities and reflection properties for trigonometric functions? What is the pythagorean identity? If #sec theta = 4#, how do you use the reciprocal identity to find #cos theta#? How do you find the domain and range of sine, cosine, and tangent? What quadrant does #cot 325^@# lie in and what is the sign? How do you use use quotient identities to explain why the tangent and cotangent function have... How do you show that #1+tan^2 theta = sec ^2 theta#? See all questions in Relating Trigonometric Functions Impact of this question 2516 views around the world You can reuse this answer Creative Commons License