How do you solve #2(y-7)^2=64#?
1 Answer
Explanation:
Consider the given equation #2(y-7)^2=64$
Now, taking the given equation, let us divide it by
So, we end up with
Now,
Let's now take the square root on both sides of the equation, giving us
Now, the square root of any square is the original value itself, so
But, what about the right-hand side of the equation?
We know that the square root of the product of any two real numbers is equal to the product of the square root of those numbers, (except when both are negative), so
We can write the square root of any value as value raised to the power of half, i.e
So, that means
That ends with
So that makes the original equation as
If you now add