Question

How do you solve `(x-3)^2=3(x-3)`?

Answer 1

`x=6`

`x=3`

Explanation:

`(x-3)^2=3(x-3)`

`x^2-6x+9=3x-9`

`x^2-9x+18=0`

`(x-6)(x-3)=0`

Hence

`x=6" "` or `" "x=3`

Hope it helped!