How do you differentiate #f(x) = (5x-4 )^(2) # using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Lithia Feb 17, 2017 #f'(x)=10(5x-4)# Explanation: #f(x)=(5x-4)^2# Chain Rule: #f'(x)=f(g(x))g'(x)# here #f(x)=x^2# and #g(x)=5x-4# #f'(x)=2(5x-4)^(2-1)(5-0)# #f'(x)=10(5x-4)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 3301 views around the world You can reuse this answer Creative Commons License