Question

How do you solve the system of equations `2x-y=71` and `3y=x` using substitution?

Answer 1

`(142/5 , 71/5)`

Explanation:

`2x-y=71` and `3y=x`

you just substitute one equation into the other
since `x=3y` you can just insert that into `2x-y=71`

`2(3y)-y=71`
`6y-6=71`
`5y=71`
`y=71/5`

then we plug this y-value into either equation
`2x-71/5=71`
`2x=284/5`
`x=284/10=142/5`

`(142/5 , 71/5)`