How do you solve $7 - \frac{5}{x} = \frac{16}{x}$ $7- \frac { 5} { x } = \frac { 16} { x }$ ?

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Answer 1 · 2017-02-18T06:20:52

$x = 3$ $x = 3$

$7 = \frac{5}{x} + \frac{16}{x}$ $7 = 5/x + 16/x$

$\Rightarrow \frac{5 + 16}{x} = 7$ $=> (5+16)/x = 7$

$\Rightarrow \frac{21}{x} = 7$ $=> 21/x = 7$

$\Rightarrow \frac{1}{x} = \frac{7}{21}$ $=> 1/x = 7 / 21$

By the reciprocal principle:

$\Rightarrow x = \frac{21}{7}$ $=> x = 21/7$

$x = 3$ $x = 3$

Which satisfies the equation given.

Answer 2 · 2017-02-18T08:08:52

$x = 3$ $x=3$

$7 - \frac{5}{x} = \frac{16}{x}$ $7 -5/x = 16/x" "$ get rid of the denominators ( $\times x$ $xx x$ )

$7 \times x - \frac{5 \times x}{x} = \frac{16 \times x}{x}$ $7color(blue)(xx x) -(5color(blue)(xx x))/x = (16color(blue)(xx x))/x$

$7 x - 5 = 16$ $7x -5 = 16" "$ add 5 to both sides

$7 x = 16 + 5$ $7x = 16+5$

$7 x = 21$ $7x = 21$

$x = 3$ $x=3$

How do you solve 7−5x=16x7- \frac { 5} { x } = \frac { 16} { x }?