Question #3e258
1 Answer
Explanation:
Here
#a_3=10#
#a_5=26#
On solving, we get
#a+4d=26#
#a+3d=10#
On substituting
#d=3#
Therefore,
#a_n = 1 + 3(n-1)#
Here
#a_3=10#
#a_5=26#
On solving, we get
#a+4d=26#
#a+3d=10#
On substituting
#d=3#
Therefore,
#a_n = 1 + 3(n-1)#