How do you find all six trigonometric function of $θ$ $theta$ if the point (-5,12) is on the terminal side of $θ$ $theta$ ?

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How do you find all six trigonometric function of $θ$ $theta$ if the point (-5,12) is on the terminal side of $θ$ $theta$ ?

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Answer 1 · 2017-02-20T04:57:27

$tan t = \frac{12}{- 5}$ $tan t = 12/-5$
${cos}^{2} t = \frac{1}{1 + {tan}^{2} t} = \frac{1}{1 + \frac{144}{25}} = \frac{25}{169}$ $cos^2 t = 1/(1 + tan^2 t) = 1/(1 + 144/25) = 25/169$
$cos t = \pm \frac{5}{13}$ $cos t = +- 5/13$
Because tan t < 0, then, cos t is negative
$cos t = - \frac{5}{13}$ $cos t = - 5/13$
$sin t = tan t . cos t = (- \frac{12}{5}) (- \frac{5}{13}) = \frac{12}{13}$ $sin t = tan t.cos t = (- 12/5)(- 5/13) = 12/13$
$sec t = \frac{1}{cos} = - \frac{13}{5}$ $sec t = 1/(cos) = - 13/5$
$csc t = \frac{1}{sin =} \frac{13}{12}$ $csc t = 1/sin = 13/12$

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How do you find all six trigonometric function of $θ$ $theta$ if the point (-5,12) is on the terminal side of $θ$ $theta$ ?

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How do you find all six trigonometric function of thetaθtheta if the point (-5,12) is on the terminal side of thetaθtheta?

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How do you find all six trigonometric function of $θ$ $theta$ if the point (-5,12) is on the terminal side of $θ$ $theta$ ?