How do you find the value of the discriminant and state the type of solutions given $9 m^{2} + 6 m + 6 = 5$ $9m^2+6m+6=5$ ?

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How do you find the value of the discriminant and state the type of solutions given $9 m^{2} + 6 m + 6 = 5$ $9m^2+6m+6=5$ ?

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Answer 1 · 2017-02-22T20:59:34

Double root at $x = - \frac{1}{3}$ $x = - 1/3$

Explanation:

Bring the equation to standard form:
$9 m^{2} + 6 m + 1 = 0$ $9m^2 + 6m + 1 = 0$
Discriminant $D = d^{2} = b^{2} - 4 a c = 36 - 36 = 0$ $D = d^2 = b^2 - 4ac = 36 - 36 = 0$
There is double-root at $x = - \frac{b}{2 a} = - \frac{6}{18} = - \frac{1}{3}$ $x = -b/(2a) = -6/18 = -1/3$

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How do you find the value of the discriminant and state the type of solutions given $9 m^{2} + 6 m + 6 = 5$ $9m^2+6m+6=5$ ?

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Explanation:

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How do you find the value of the discriminant and state the type of solutions given 9m2+6m+6=59m^2+6m+6=5?

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How do you find the value of the discriminant and state the type of solutions given $9 m^{2} + 6 m + 6 = 5$ $9m^2+6m+6=5$ ?