How do you multiply (3k ^ { 4} d ^ { 6} ) ( 6d ^ { 3} j ^ { 4} ) (3k4d6)(6d3j4)?

1 Answer

Using indices first law, you can multiply the two d units together. 3k^4*6d^(6+3)*j^43k46d6+3j4 and thus the final answer would be 18k^4d^9j^418k4d9j4

Explanation:

The trick is to put the d units together. 6d^3*d^66d3d6 would equal to 6*d^(3+6)=6d^96d3+6=6d9

Grouping using brackets where appropriate to highlight the relationships.

(3xx6)(k^4)(d^6d^3)(j^4)(3×6)(k4)(d6d3)(j4)

18k^4d^9j^418k4d9j4