How do you solve $-2r + 6r + - 2r = - 20$ ?

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Answer 1 · 2017-02-25T14:33:08

$-2r+6r-2r=-20$
$implies (-2+6-2)r=-20$
$implies (2)r=-20$
$implies r=-20/2=-10$
$implies r=-10$

How do you solve -2r + 6r + - 2r = - 20-2r + 6r + - 2r = - 20?