What is the value of #24 -:2^2x(x-4)# for #x=7#?

1 Answer
Mar 2, 2017

#2/7#

Explanation:

Replace all the instances of #x# with the number 7:

#24/(2^2x(x-4))=24/(4*7(7-4))=24/(28*3)=24/84#

Simplify the final answer by dividing the numerator and denominator by 12:

#24/84=color(red)(2/7)#