What force will a proton experience in a uniform electric field whose strength is $2.00 \cdot 10^{5}$ $2.00 * 10^5$ newtons per coulomb?

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Answer 1 · 2017-03-05T12:23:44

$3.2 \times 10^{- 14} N$ $3.2 xx 10^-14N$

A proton has a charge of $1.6 \times 10^{- 19} C$ $1.6xx10^-19C$ .

Therefore, by

$F = Q E$ $F = QE$

where $F$ $F$ is force, $Q$ $Q$ is charge and $E$ $E$ is electric field strength,

$F = 1.6 \times 10^{- 19} \times 2 \times 10^{5} = 3.2 \times 10^{- 14} N$ $F = 1.6 xx 10^-19 xx 2 xx 10^5 = 3.2 xx 10^-14N$

What force will a proton experience in a uniform electric field whose strength is 2.00⋅1052.00 * 10^5 newtons per coulomb?