Two charges of 2C and 6C are positioned on a line at points 3 and 4, respectively. What is the net force on a charge of 5C at 0?

1 Answer
Mar 5, 2017

6.9×109N attractive force.

Explanation:

The electrical force is given by

F=kQ1Q2r2

where k9×109 is Coulomb's constant, Q is the charge and r is the distance between them.

The force between the 2C and 5C charges is

F=9×109×2×532=1010N

and, between the 6C and 5C charges, is

F=9×109×6×542=1.69×1010

The net force is the sum of the forces, so

Fnet=1010+(1.69×1010)=6.9×109N

This is in the negative direction, which is the same direction as the force between the 5C and 6C charges, which must attract because the are opposites. Therefore, the net force is attractive, too.