How do you solve $5 x^{2} + 3 x - 55 = 5$ $5x ^ { 2} + 3x - 55= 5$ ?

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Answer 1 · 2017-03-07T05:21:47

$\frac{- 3 + \sqrt{1209}}{10}$ $(-3+sqrt1209)/10$ or $\frac{- 3 - \sqrt{1209}}{10}$ $(-3-sqrt1209)/10$

$5 x^{2} + 3 x - 55 = 5$ $5x^2 + 3x - 55 = 5$

= $5 x^{2} + 3 x - 60 = 0$ $5x^2 + 3x - 60 = 0$

standard equation of quadratic equation,
$a x^{2} + b x + c = 0$ $ax^2 + bx + c = 0$

Here,
a = 5, b = 3 and c = 60

by formula,
x = $\frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $[-b +- sqrt(b^2 - 4ac)]/(2a)$

So, x = $\frac{- 3 \pm \sqrt{9 + 1200}}{10}$ $[-3 +- sqrt(9 + 1200)]/(10)$

$therefore$ x = $(-3+sqrt1209)/10$ or $(-3-sqrt1209)/10$

How do you solve 5x ^ { 2} + 3x - 55= 55x2+3x−55=55x ^ { 2} + 3x - 55= 5?