Question

How do you solve the system of equations `\frac { x } { 4} + \frac { y } { 8} = - 3` and `\frac { x } { 2} - \frac { y } { 4} = 1`?

Answer 1

x = -5 and y = -14

Explanation:

let `x/4 + y/8 = -3` be as A
and,
`x/2 - y/4 = 1` be as B

now.
multiply whole equation A by 8, we get,
2x + y = -24

also,
multiply whole equation B by 4, we get,
2x - y = 4

Solving both the equations we get,
x = -5 and y = -14