How do I divide and simplify $\frac{\sqrt{300 x^{18}}}{\sqrt{2 x}}$ $sqrt(300x^18)/sqrt(2x)$ ?

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How do I divide and simplify $\frac{\sqrt{300 x^{18}}}{\sqrt{2 x}}$ $sqrt(300x^18)/sqrt(2x)$ ?

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Answer 1 · 2017-03-08T09:39:07

$5 \cdot \sqrt{6} \cdot x^{8} \sqrt{x}$ $5*sqrt(6)*x^8sqrtx$

Explanation:

$\frac{\sqrt{300 x^{18}}}{\sqrt{2 x}} = \sqrt{\frac{300 x^{18}}{2 x}} = \sqrt{150 x^{17}} = \sqrt{25 \cdot 6 x^{17}} = 5 \sqrt{6 x^{17}} = 5 \cdot \sqrt{6} \cdot \sqrt{x^{17}} = 5 \cdot \sqrt{6} \cdot x^{8} \sqrt{x}$ $sqrt(300x^18)/sqrt(2x) = sqrt((300x^18)/(2x)) = sqrt(150x^17) = sqrt(25*6 x^17) = 5 sqrt(6 x^17) = 5*sqrt(6)*sqrt(x^17) = 5*sqrt(6)*x^8sqrtx$

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How do I divide and simplify $\frac{\sqrt{300 x^{18}}}{\sqrt{2 x}}$ $sqrt(300x^18)/sqrt(2x)$ ?

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How do I divide and simplify $\frac{\sqrt{300 x^{18}}}{\sqrt{2 x}}$ $sqrt(300x^18)/sqrt(2x)$ ?