Question #142e0

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Answer 1 · 2017-03-08T15:49:29

#rArr costheta = 5/sqrt61#

#tan theta= -6/5#

Using the identity in trigonometry,
#1 + tan^2 theta= sec^2theta#

#rArr 1+36/25= sec^2theta#

#rArr 61/25= sec^2theta#

#rArr sectheta = sqrt61/5#

Also, #cos theta= 1/sec theta#

#rArr costheta = 5/sqrt61#