Question

How do you use the properties of logarithms to expand `log_5 (5/x)`?

Answer 1

`log_5 (5/x)=log_5 5-log_5 x=1-log_5 x`

Explanation:

`log_5 (5/x)=log_5 5-log_5 x`--> Use the property `log_b (x/y)=log_bx/log_b y`

`=1-log_5x` ---> Use property `log_a a =1`