The sum of the digits of a two-digit number is 11. The tens digit is one less than three times the ones digit. What is the original number?

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Answer 1 · 2017-03-10T05:29:25

Number = 83

Let the number in unit place be #x# & the number in tens place be #y#.

According to the first condition,

#x+y=11#

According to the second condition,

#x=3y-1#

Solving two simultaneous equation for two variable:

#3y-1+y=11#

#4y-1=11#

#4y=12#

#y=3#

#x=8#

The original number is #83#