The sum of the digits of a two-digit number is 11. The tens digit is one less than three times the ones digit. What is the original number?

Question

6809 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-10T05:29:25

Number = 83

Let the number in unit place be #x# & the number in tens place be #y#.

According to the first condition,

#x+y=11#

According to the second condition,

#x=3y-1#

Solving two simultaneous equation for two variable:

#3y-1+y=11#

#4y-1=11#

#4y=12#

#y=3#

#x=8#

The original number is #83#