Question

What is the acceleration of a car stopping with 254 N of force if it has a mass of 2500 kg?

Answer 1

`-0.1016ms^(-2)`

Explanation:

using N2L

#F=ma~

`254=2500a`

`a=254/2500=0.1016ms^(-2)`

since this is STOPPING the car it is a negative acceleration

so `a=-0.1016ms^(-2)`

Answer 2

`F=ma`
`254=(2500)a`
`254/2500=a`
`0.1016m/s²=a`
when the car is stopping, negative acceleration(deceleration) has been produced
`a=-0.1016 m/s²`