How do you solve #\frac { 2x } { 3} + 2= \frac { x } { 4} - 3#?

Question

780 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-12T04:24:54

#x=12#

Let's simplify the equation by subtracting 2 from both sides and get:

#(2x)/3=x/4-5#

Now let's multiply both sides by a common denominator to eliminate the fractions, in this case we'll use #12#...

#(2x)/3*12/1=x/4*12/1-(5*12)#

(Remember we must multiply both terms on the right, i.e. both #x/4# and #-5#)

Simplify:

#(2x)/cancel(3)*12/1=x/cancel(4)*12/1-(5*12)#

And get:

#8x=3x-60#

Subtract #3x# from both sides:

#8x-color(red)(3x)=cancel(3x-color(red)(3x))-60#

And get:

#5x=60#

Divide by 5:

#(5x)/5=60/5#

And find that:

#x=12#