How do you write an equation of a line passing through (2, -8), perpendicular to #4x+5y=7#?
1 Answer
Explanation:
First, you would want to get only
Then divide by 5:
Product of slopes of two perpendicular lines is
Now, make your new equation in point-slope format:
Now, to figure out the
Multiply
Adding
Make -8 and 5/2 have a common denominator:
Then you can put that into the point-slope formula and you're done!
graph{(y-5/4x+21/2)(5y-7+4x)=0 [-8.62, 11.38, -8.44, 1.56]}