Question

How do you find the zeros, if any, of `y= -17x^2+6x-3`using the quadratic formula?

Answer 1

No real roots

Explanation:

`-b+-sqrt(b^2-4(a)(c))/(2a)`
`a=-17`
`b=6`
`c=-3`
substitute
`-(6)+-sqrt((6)^2-4(-17)(-3))/(2(-17))`
since `6^2-4(-17)(-3)` is negative, you cannot take the square root of it and get real numbers. Therefore there are no real roots