Given #g(x) = -2x^2 - 9# how do you find g(3)?

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Answer 1 · 2017-03-16T00:39:58

#g(3)=-27#

You would substitute 3 for each x...
#-2(3)^2-9#
#-2(9)-9#
#-18-9#
#-27#
#g(3)=-27#

Answer 2 · 2017-03-16T00:41:14

#g(3)=-27#

Given:

#g(x)=-2x^2-9#

Solve if #g(x)=g(3)#

Substitute #3# for #x#.

#g(3)=-2(3)^2-9# #larr# parentheses and exponents first

#g(3)=-2xx9-9# #larr# multiply #-2xx9#

#g(3)=-18-9#

#g(3)=-27#