How do you solve #a/10=2/5#?
↳Redirected from
"What are quantum numbers?"
For this problem, we need to find the LCD (least common denominator). In this case, it is #10# as
#5 * 2= 10#
If we multiply the denominator by #2#, then we also need to multiply the numerator by #2#
#2 * 2= 4#
So
#a/10 = (2 * 2)/(5 * 2)#
#a/10 = 4/10#
#a=4 #
#color(blue)("Preamble")#
You need to manipulate the equation so that you have #a# on its own on one side of the equals sign and everything else on the other side.
The left side we have #1/10xxa# So if we can change the #1/10# into 1 we have: #1xxa# which is the same as just #a#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Answering the question")#
Multiply both sides by #color(red)(10)#
#color(green)(a/10color(red)(xx10)" "=" " 2/5color(red)(xx10))#
#color(green)(a color(red)(xx)color(red)(10)/10" "=" " 2/5color(red)(xx10))#
But #10/10=1#
#a=4#
