How do you simplify $\frac{- 13 a^{4}}{39 a^{12}}$ $\frac { - 13a ^ { 4} } { 39a ^ { 12} }$ ?

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Answer 1 · 2017-03-18T21:55:38

$- \frac{1}{3 a^{8}}$ $-1/(3a^8)$

1. $- \frac{13}{39}$ $-13/39$ = $- \frac{1}{3}$ $-1/3$

2. $\frac{a^{4}}{a^{12}}$ $a^4/a^12$ = $a^{4 - 12}$ $a^(4-12)$ = $\frac{1}{a^{8}}$ $1/a^8$

3.ANSWER: $- \frac{1}{3 a^{8}}$ $-1/(3a^8)$

How do you simplify −13a439a12\frac { - 13a ^ { 4} } { 39a ^ { 12} }?