How do you graph #2x+5y=10# using intercepts?
2 Answers
Graph of
#y=-2/5x+2#
graph{-2/5x + 2 [-7, 7, -7, 7]}
Explanation:
The equation of a straight line with gradient
#y=mx+c#
You have been given all the information you need but to get to this format, need to rearrange:
#2x+5y=10#
subtracting
#-2x+2x+5y=10-2x#
#5y=-2x+10#
Dividing through both sides by
#(5y)/5=(-2x)/5+10/5#
#y=-2/5x+2#
So now it can be seen that the
The
#0=-2/5x+2#
To find the value of
#0+2/5x=-2/5x+2+2/5x#
#2/5x=2#
#2/5x xx5/2=2xx5/2#
#x=10/2=5#
So the
This means that the graph will cross through:
the
#x# -intercept#(0,5)# ; andthe
#y# -intercept#(2,0)# .
You can mark these on your graph and then draw a line through them both.
Graph of
#y=-2/5x+2#
graph{-2/5x + 2 [-7, 7, -7, 7]}
see explanation.
Explanation:
To find the intercepts.
#• " let x = 0, in the equation, for y-intercept"#
#• " let y = 0, in the equation, for x-intercept"#
#x=0to0+5y=10toy=2larrcolor(red)" y-intercept"#
#y=0to2x+0=10tox=5larrcolor(red)" x-intercept"# Plot the points (0 ,2) , (5 ,0) and draw a straight line through them. This is the graph of 2x + 5y = 10
graph{-2/5x+2 [-10, 10, -5, 5]}