How do you solve #5^(2x + 3)\leq 125#?

1 Answer
Grace
Mar 22, 2017

#x<=0#

Explanation:

We know that #5^3 = 125#. Since #5^(2x+3)# is less than or equal to #125#, this must mean #2x + 3# is less than or equal to #3#, as #2x+3 = 3# would give #125#, and any power less than #3# would give a number less than #125#.

Now, we have an inequality to solve:

#2x+3 <= 3#

#2x <= 0 #

#x <= 0#

Therefore, we get the final answer to be #x<=0#.

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