What is the perimeter of a triangle with corners at #(6 ,4 )#, #(8 ,2 )#, and #(5 ,7 )#?

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Answer 1 · 2017-03-22T15:19:36

Perimeter of Triangle = #11.8216566798# units
(or) #√(8) + √(34) + √(10) #

Vertices of Triangle are #(6,4),(8,2),and (5,7) #
Distance #= sqrt[(x2-x1)^2+(y2-y1)^2]#

Using Distance Formula

Find distance between (6,4),(8,2) and (8,2),(5,7) and (5,7),(6,4)

Then we get,
Distance between (6,4),(8,2) = #sqrt8#

Distance between (8,2),(5,7) = #sqrt34#

Distance between (5,7),(6,4) = #sqrt10#

Add them we get Perimeter of the Triangle

#√(8) + √(34) + √(10) = 11.8216566798# units

Reference