What is the simplest radical form for #sqrt(145)#?
2 Answers
Mar 28, 2017
Explanation:
There is no simple form for this.
Let's try using the factors of
#sqrt145=sqrt145*sqrt1#
#sqrt145=sqrt29*sqrt5#
This cannot be broken into any simpler forms so there is no simple from for
Mar 28, 2017
Explanation:
The prime factorisation of
#145 = 5*29#
Since this has no square factors, there is no simpler radical form than
Note however that
As a result, its square root has a very simple form as a continued fraction:
#sqrt(145) = [12;bar(24)] = 12+1/(24+1/(24+1/(24+1/(24+1/(24+...)))))#