#C_2H_4 + 3O_2 -> 2CO_2 +2H_2O#. If you start with 45 grams of ethylene (#C_2H_4#), how many grams of carbon dioxide will be produced?

1 Answer
NGBRO
Mar 29, 2017

141.416g

Explanation:

#"No. of mol of ethylene"=45/(2*12+4*1)~~1.607mol#

#"No. of mol of "CO_2" produced"=2*1.607=3.214mol#

#"Mass of "CO_2"=3.214*(12+2*16)=141.416g#

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