How do you divide #\frac { \frac { 6u } { u ^ { 2} + 2u - 35} } { \frac { 2} { u - 5} }#?

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Answer 1 · 2017-03-29T22:36:52

#(3u)/(u+7) #

Rewrite it as a division question:

#(6u)/(u^2+2u-35) -: 2/(u-5)#

Flip the fraction on the right side and rewrite it as a multiplication question:

#(6u)/(u^2+2u-35) xx (u-5)/2#

Factor out a #u-5# from the bottom of the left fraction and cancel it with the other other #u-5#:

#(6u)/(u+7) xx1/2#

Now take #2# out of #6#. You're left with #1/1# on the right side so that doesn't matter. So you have:

#(3u)/(u+7) #