Question #7bc10

1 Answer
Veerupaksh
Mar 30, 2017

sqrt3

Explanation:

9sqrt8 = 9sqrt(2^3) = 3^2*2^(3/2)
6sqrt6 = 3*2*sqrt(3*2) = 3^1*2^1*3^(1/2)*2^(1/2) = 3^(3/2)*2^(3/2)

therefore (9sqrt8) / (6sqrt6) = (3^2*2^(3/2))/(3^(3/2)*2^(3/2))

= (3^(2 - 3/2)) * (2^(3/2 - 3/2))
= 3^(1/2)*1 = 3^(1/2) = sqrt(3)

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