Question

Question #a6b93

Answer 1

`{x:x=pi/6, (5pi)/6, (7pi)/6}`

Explanation:

There are two possibilities here, that `sqrt3-cotx=0` and that `2-cscx=0`. Each must be considered individually.

Case 1: `sqrt3-cotx=0`
`cotx=sqrt3`
`tanx=1/sqrt3`
Knowing special angles, `x=pi/6, (7pi)/6`

Case 2: `2-cscx=0`
`cscx=2`
`sinx=1/2`
Knowing special angles, `x=pi/6, (5pi)/6`

Therefore `{x:x=pi/6, (5pi)/6, (7pi)/6}`