Question #a6b93

1 Answer
Mar 31, 2017

{x:x=pi/6, (5pi)/6, (7pi)/6}{x:x=π6,5π6,7π6}

Explanation:

There are two possibilities here, that sqrt3-cotx=03cotx=0 and that 2-cscx=02cscx=0. Each must be considered individually.

Case 1: sqrt3-cotx=03cotx=0
cotx=sqrt3cotx=3
tanx=1/sqrt3tanx=13
Knowing special angles, x=pi/6, (7pi)/6x=π6,7π6

Case 2: 2-cscx=02cscx=0
cscx=2cscx=2
sinx=1/2sinx=12
Knowing special angles, x=pi/6, (5pi)/6x=π6,5π6

Therefore {x:x=pi/6, (5pi)/6, (7pi)/6}{x:x=π6,5π6,7π6}