How do you find the period of # h(t) = 4*sin(3t) + 3*sin(tsqrt3)#?

1 Answer
Wataru
Apr 1, 2017

h(t) is not periodic, so you cannot find it.

Explanation:

Since the period of #sin(x)# is #2pi#, the period of #4sin(3t)# is #{2pi}/{3 }#, and the period of #3sin(sqrt{3}t)# is #{2pi}/sqrt{3}#. The period of the sum of those two periodic function would be the least common multiple of the two periods; however, there is no such common multiple. Hence, #h(t)# is not periodic.

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