How do you find the period of $h (t) = 4 \cdot sin (3 t) + 3 \cdot sin (t \sqrt{3})$ $h(t) = 4sin(3t) + 3sin(tsqrt3)$ ?

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How do you find the period of $h (t) = 4 \cdot sin (3 t) + 3 \cdot sin (t \sqrt{3})$ $h(t) = 4sin(3t) + 3sin(tsqrt3)$ ?

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Answer 1 · 2017-04-01T06:30:26

h(t) is not periodic, so you cannot find it.

Explanation:

Since the period of $sin (x)$ $sin(x)$ is $2 π$ $2pi$ , the period of $4 sin (3 t)$ $4sin(3t)$ is $\frac{2 π}{3}$ ${2pi}/{3 }$ , and the period of $3 sin (\sqrt{3} t)$ $3sin(sqrt{3}t)$ is $\frac{2 π}{\sqrt{3}}$ ${2pi}/sqrt{3}$ . The period of the sum of those two periodic function would be the least common multiple of the two periods; however, there is no such common multiple. Hence, $h (t)$ $h(t)$ is not periodic.

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How do you find the period of $h (t) = 4 \cdot sin (3 t) + 3 \cdot sin (t \sqrt{3})$ $h(t) = 4sin(3t) + 3sin(tsqrt3)$ ?

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How do you find the period of h(t)=4⋅sin(3t)+3⋅sin(t√3) h(t) = 4*sin(3t) + 3*sin(tsqrt3)?

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How do you find the period of $h (t) = 4 \cdot sin (3 t) + 3 \cdot sin (t \sqrt{3})$ $h(t) = 4sin(3t) + 3sin(tsqrt3)$ ?