How do you solve $5x^2 + 7x = 6$ using the quadratic formula?

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Answer 1 · 2017-04-01T19:20:51

Using the quadratic formula, $x =$ $(-b+- sqrt(b^2-4ac))/(2a)$ , we get that $x =-2, 0.6$

Rearrange the equation so that it becomes: $5x^2+7x-6=0$

The quadratic formula is: $x =$ $(-b+- sqrt(b^2-4ac))/(2a)$

In our equation above,
$a=5$
$b=7$
$c=-6$

Plugging these values into the quadratic equation gives:

$x =$ $(-7+- sqrt(7^2-4(5)(-6)))/(2(5))$

$x =$ $(-7+- sqrt(49+120))/(10)$

$x =$ $(-7+- sqrt(169))/(10)$

$x =$ $(-7+- 13)/(10)$

$x =-2, 0.6$

How do you solve 5x^2 + 7x = 6 5x^2 + 7x = 6 using the quadratic formula?