How do you find the remaining trigonometric functions of #theta# given #cottheta=m/n# where m and n are both positive?
1 Answer
Explanation:
First let's identify the ones that are left.
But
Using the pythagorean theorem
#hypoten use^2=opposite^2+adjacent^2#
#hypoten use=sqrt(opposite^2+adjacent^2)#
#hypoten use=sqrt(n^2+m^2)#