Question #904a3

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Question #904a3

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Answer 1 · 2017-04-03T17:04:38

K = $1.5$ $1.5$ x $10^{2}$ $10^2$

Explanation:

$C O (g)$ $CO(g)$ + $2 H_{2} (g)$ $2H_2 (g)$ ⇌ $C H_{3} O H (g)$ $CH_3OH(g)$
Kp = $2.26$ $2.26$ x $10^{4}$ $10^4$

where K = $2.26$ $2.26$ x $10^{4}$ $10^4$ at $298$ $298$ K.
If we were to divide the coefficients of above reaction equation by $2$ $2$ , we would get the following equation:

$\frac{1}{2} C O (g)$ $1/2 CO(g)$ + $H_{2} (g)$ $H_2 (g)$ ⇌ $\frac{1}{2} C H_{3} O H (g)$ $1/2 CH_3OH(g)$

Now K = $[C H_{3} O H (g)]^{0.5}$ $[CH_3OH(g)]"^0.5$ /[ $C O {(g)}^{0.5}$ $CO(g)^0.5$ ]. [ $H_{2} (g)$ $H_2 (g)$ ]

threfore
K= √(kp)...........................square root of Kp
K = √ ( $2.26$ $2.26$ x $10^{4}$ $10^4$ )
K = $150.33$ $150.33$
K = $1.5$ $1.5$ x $10^{2}$ $10^2$

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Question #904a3

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