How do you solve #k^ { 2} - 3k - 88= 0#?
2 Answers
and
Explanation:
Factor
Set each pair equal (
(k-11) x ( k+8) Break the trinomial into two binomials and solve for k
k = + 11 k = -8
Explanation:
The C value in the trinomial
The B value in the the trinomial is negative this means that the negative factor of 88 must be larger than the positive factor by 3
There are several factor combinations for 88 : 1 x 88, 2 x 44 , 4 x 22 and 8 x 11. 8 x 11 has a difference of three.
So 11 must be negative since it is larger and 8 must be positive
k = -8 and + 11